[tex]\displaystyle|\Omega|=12\cdot 20=240\\|A|=\sum_{k=1}^{12}(20-k)=\sum_{k=1}^{12}20-\sum_{k=1}^{12}k=12\cdot20-\dfrac{(1+12)}{2}\cdot 12=240-13\cdot 6=\\\\=240-78=162\\\\P(A)=\dfrac{162}{240}=\dfrac{27}{40}[/tex]
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[tex]\displaystyle|\Omega|=12\cdot 20=240\\|A|=\sum_{k=1}^{12}(20-k)=\sum_{k=1}^{12}20-\sum_{k=1}^{12}k=12\cdot20-\dfrac{(1+12)}{2}\cdot 12=240-13\cdot 6=\\\\=240-78=162\\\\P(A)=\dfrac{162}{240}=\dfrac{27}{40}[/tex]