1)Z def. stęż. procemt.20g soli----100g roztworuxg soli------200g roztworux=20*200/100x=40g soliDolewamy 50g wody i dodaje 20g NaOH60g(40g+20g) soli----270g roztworu(200g+50g+20g)xg soli-----100g roztworux=60*100/270x=22,2g solix=22,2%OTRZYMAMY ROZTWÓR 22,2%2)30g 30%..............................x - 20........................x%40g 20%.............................30 - x30/40 = x-20/30-x30(30-x) = 40(x-20)900-30x = 40x - 80070x = 1700x = 24,28%
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1)
Z def. stęż. procemt.
20g soli----100g roztworu
xg soli------200g roztworu
x=20*200/100
x=40g soli
Dolewamy 50g wody i dodaje 20g NaOH
60g(40g+20g) soli----270g roztworu(200g+50g+20g)
xg soli-----100g roztworu
x=60*100/270
x=22,2g soli
x=22,2%
OTRZYMAMY ROZTWÓR 22,2%
2)
30g 30%..............................x - 20
........................x%
40g 20%.............................30 - x
30/40 = x-20/30-x
30(30-x) = 40(x-20)
900-30x = 40x - 800
70x = 1700
x = 24,28%