~Kestimbangan benda tegar~
kelas= XI
------->momen gaya.
∑Fy=0
w-Nb=0
w=Nb
Nb=(300+700)
=1000N
∑Fx=0
Na-fg=0
fg=Na
Na=μ×Nb
∑T=0
w.L/2-w.L+Fg.L=0
1000.3/2-1000.3+μ.Nb=0
1500-3000+u.1000.4=0
-1500=-4000μ
μ=0,375
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~Kestimbangan benda tegar~
kelas= XI
------->momen gaya.
∑Fy=0
w-Nb=0
w=Nb
Nb=(300+700)
=1000N
∑Fx=0
Na-fg=0
fg=Na
Na=μ×Nb
∑T=0
w.L/2-w.L+Fg.L=0
1000.3/2-1000.3+μ.Nb=0
1500-3000+u.1000.4=0
-1500=-4000μ
μ=0,375