" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Obliczenia:
V = 500 cm3 = 0,5 dm3
Cm = 0,1 mol/dm3
n = 0,05 mola NaOH
M = 40 g/mol
m = 40 * 0,05 = 2 g NaOH
Aby otrzymac 500 cm3 0,1-molowego NaOH nalezy w zlewce, zawierajacej 498 g wody (bo 500 - 2g sub = 498g) rozpuscic 2 g wodorotlenku sodu.