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z zapisu reakcji wynika ze 2 mole CuO reaguje z 1 molem C
Mcuo= 81 g
2 mole= 2x 81= 162 g
ukladamy proporcje:
162 g (CuO) ----- 12 g (C)
72 g-------------x
x= 72x 12/ 162= 5,3 g C