Oblicz ciężar deski sosnowej o wymiarach a=4m , b=20cm, c=5cm. Gęstość drewna 800 kg/m3
dane
a=4m
b=20cm=0.2m
c=5cm=0.05m
ro=800kg/m³
P=?
V=a*b*c
V=4*0.2*0.05=0.04m³
m=V*ro
m=0.04*800=32kg
a ciezar to
P=m*g
P=32*10=320N
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dane
a=4m
b=20cm=0.2m
c=5cm=0.05m
ro=800kg/m³
P=?
V=a*b*c
V=4*0.2*0.05=0.04m³
m=V*ro
m=0.04*800=32kg
a ciezar to
P=m*g
P=32*10=320N