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p=1,27 x 10 do minus 5[Pa]
gęstość oznaczamy d=1000[kg/m3]
szukane:
h=?[m]
wzory:
p= p0 +dgh wyznaczamy h=?
p0=1013,75[hPa]=101375[N/m2],
wyznaczam h=?
h=(p-p0)/(d x g):
jednostka:
[h]= [(N/m2)/(kg/m3)]=[m]:
obliczenia:
podstaw do wzoru
[h]=[ (p-p0 )/d
pods4aw i obl;cz