1.Oblicz jaki nacisk wywiera na podłoże walec żelazny o gęstości= 8000kg/m^3 o wymiarach h=2m średnica=20 cm.
ρ = 8000 kg/m³
h = 2m
d = 20 cm
N = ?
r = 1/2 d = 10 cm = 0,1 m
N = mg
m = ρV
V = Sh
S = πr²
N = ρπr²hg = 8000 * 3,14 * 0,1²*2*10=5024 kg
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ρ = 8000 kg/m³
h = 2m
d = 20 cm
N = ?
r = 1/2 d = 10 cm = 0,1 m
N = mg
m = ρV
V = Sh
S = πr²
N = ρπr²hg = 8000 * 3,14 * 0,1²*2*10=5024 kg