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Verified answer
Dik: gr=18 gMr=180
p=500 g
Kf=1,86°C/m
Dit:ΔTf
Jwb:
ΔTf = Kf × gr/Mr × 1000/p
ΔTf = 1,86 × 18/180 × 1000/500
ΔTf= 1,86 × 0,2=0,372 °C