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s² = r² + t²
s² = 7² + 24²
s² = 49 + 576
s² = 625
s = √625
s = 25
(mencari luas sisi kerucut/selimut kerucut)
L = π . r . s
L = 22/7 . 7 . 25
L = 22 . 25
L = 550
Jadi, luas sisi/selimut kerucut adalah 550 cm²
= 22/7 x 7 (7 + 25) = √7² + 24²
= 704 cm² = √49 + 576
= √625
= 25 cm