r = 28 ÷ 2 = 14 cm
6. Tabung nya tanpa tutup.
L = π × r × (r + 2 × t)
= 22/7 × 14 × (14 + 2 × 34)
= 22/7 × 14 × (14 + 68)
= 22/7 × 14 × 82
= 22 × 2 × 82
= 3.608 cm²
Gak ada pilihannya
7. L = ½ × 4 × π × r²
= ½ × 4 × 22/7 × 14 × 14
= 2 × 22 × 2 × 14
= 1.232 cm²
Jawaban: A.
8. Luas gabungan = Luas selubung tabung + Luas setengah bola
= 3.608 + 1.232 = 4.840 cm²
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r = 28 ÷ 2 = 14 cm
6. Tabung nya tanpa tutup.
L = π × r × (r + 2 × t)
= 22/7 × 14 × (14 + 2 × 34)
= 22/7 × 14 × (14 + 68)
= 22/7 × 14 × 82
= 22 × 2 × 82
= 3.608 cm²
Gak ada pilihannya
7. L = ½ × 4 × π × r²
= ½ × 4 × 22/7 × 14 × 14
= 2 × 22 × 2 × 14
= 1.232 cm²
Jawaban: A.
8. Luas gabungan = Luas selubung tabung + Luas setengah bola
= 3.608 + 1.232 = 4.840 cm²
Jawaban: A.