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<> 2πr = 75,36
<> 2 . 3,14 . r = 75,36
<> r = 12
s² = t² + r² = 16² + 12² = 256 + 144 = 400
s = √400 = 20
Luas selimut
= π . r . (r + s)
= 3,14 . 12 . (12 + 20)
= 1205,76
Jadi, luas selimut kerucut tersebut 1205,76 cm²