Question

Luas selimut kerucut yang panjang jari jari alasnya 10cm,tinggi 24cm,dan phi=3,14 adalah...

Answer 1

R = 10 cm, t = 24 cm, phi= 3,14
maka s = √r^2 + t^2 = √10^2 + 24^2 = √100 + 576 =✓676 = 26

selimut kerucut =π × r × s = 3,14 × 10 × 26 = 816,4 cm^2