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t=24cm
Dit: l. selimut...?
Jb: t²=√r²-s²
24²=√10²-s²
(24)²=(10²-s²)
576=100-s²
s²=676
s=√676=26cm
l. selimut=Πrs
=3,14×10×26
=816,4cm²
=√100 + 576
= √676
= 26
luas selimut kerucut /\rs
3,14. 10. 26
= 3,14. 260 =816,4 cm