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diameter 14 berarti r nya 7
luas selimut = phi . r . s
550 = 22/7. 7. s
550 = 22 s
s= 25
t^2 = s^2 - r^2
t^2 = 625- 49
t^2 = 576
t= 24
0k
d = 14 cm, maka r = 7 cm
πrs = 550
22/7 × 7 × s = 550
22s = 550
s = 550/22
s = 25
Tinggi = √25² - 7²
= √625 - 49
= √576
= 24 cm