Question

Luas selimut keeucut diketahui 24cm².jika jari2 alasnya 6cm hitunglah panjang garis pelukis dan tinggi kerucut tersebut? (gunakan phi=22_7)

Answer 1

Lslmt = π r s
24 = 22/7 x 6 x s
s = 24 / (132/7)
s = 24 x 7/132
s = 168/132
s = 24

t = akar (s^2 - r^2)
t = akar ((24)^2 - 6^2)
t = akar (576 - 36)
t = akar (540)
t = 23,23