[tex]s = \sqrt{ {r}^{2} + {t}^{2} } = \sqrt{ {7}^{2} + {24}^{2} } \\ \sqrt{49 + 576} = \sqrt{625} = 25 \\ \\ luas \: permukaan \: kerucut \\ \pi \times r(r + s) \\ \frac{22}{7} \times 7(7 + 25) \\ 22(32) \\ 704 \: {cm}^{2} [/tex]
Jawaban:
704 cm²
Penjelasan dengan langkah-langkah:
Lp(kerucut)= πr(r + s)
Diket: r = 7 cm, t = 24
S= √ 24² + 7⁷ = √576 + 49 = √625 = 25 cm
Lp = 22/7 × 7 (7 + 25)= 22×32= 704 cm²
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
[tex]s = \sqrt{ {r}^{2} + {t}^{2} } = \sqrt{ {7}^{2} + {24}^{2} } \\ \sqrt{49 + 576} = \sqrt{625} = 25 \\ \\ luas \: permukaan \: kerucut \\ \pi \times r(r + s) \\ \frac{22}{7} \times 7(7 + 25) \\ 22(32) \\ 704 \: {cm}^{2} [/tex]
Jawaban:
704 cm²
Penjelasan dengan langkah-langkah:
Lp(kerucut)= πr(r + s)
Diket: r = 7 cm, t = 24
S= √ 24² + 7⁷ = √576 + 49 = √625 = 25 cm
Lp = 22/7 × 7 (7 + 25)= 22×32= 704 cm²