Question

Luas permukaan bangun tersebut adalah....

A. 704 cm²
B. 1.708 cm²
C. 1.232 cm²
D. 1.386 cm²

tolong pakai caranya....

Answer 1

31)
jari2 kerucut
= jari2 tabung
= 1/2 x diameter tabung
= 1/2 x 14
= 7 cm

tinggi kerucut (t)
= 36-12
= 24 cm

garis pelukis kerucut (s)
= √(r²+ t²)
= √(7²+ 24²)
= √(49 + 576)
= √625
= 25 cm

maka,
Luas permukaan kedua bangun (Lp)
= Lp tabung tanpa tutup + Luas selimut kerucut
= (phi x r x (r+2t)) + (phi x r x s)
= (22/7 x 7 x (7+2.12)) + (22/7 x 7 x 25)
= (22 x (7+24)) + (22 x 25)
= (22 x 31) + 550
= 682 + 550
= 1.232 cm² (c)