luas permukaan balok yang memiliki ukuran panjang 8 cm² dan lebar 11 cm adalah 366 cm² tinggi balok tersebut adalah
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L = 2(p × L + p × t + L × t)
366 = 2(8 × 11 + 8 × t + 11 × t)
366 = 2(88 + 8t + 11t)
366 = 2(88 + 19t)
366/2 = 88 + 19t
183 = 88 + 19t
19t = 183 - 88
19t = 95
t = 95/19
t = 5 cm