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Luas permukaan limas persegi dengan tinggi 12 cm dan keliling alasnya 40 cm adalah
keliling alas = 4s
4s = 40
s = 10 cm
Tinggi segitiga = 13 cm ( triple phytagoras 12,5,13)
Luas permukaan = Luas Alas + Luas sisi tegak
= s.s + 4(a.t/2)
= 10.10 + 4 (10.13/2)
= 100 + 260
= 360 cm²
Mohon maaf apabila ada kesalahan