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379, 94= 3, 14 x r^2
r^2= 379. 94/ 3,14
r^2= 121
r=
r= 11
d= 2 xr
=2 x 11
=22
dit: d=.....?
jawab: L = πr²
379,94 = 3,14×r²
r² = 379,94÷3,14
r² = 121
r = √121
r = 11
jadi diameter lingkarannya adalah 22 karena d = 2r =2×11 =22