ApLik4si InTeg12aL
Luas
= 2 ∫√(x + 1) dx [8...0]
= 2 ∫(x + 1)^1/2 d(x + 1)
= 4/3 (x + 1)^3/2
= 4/3 ( (8 + 1)^3/2 - (0 + 1)^3/2 )
= 4/3 (27 - 1)
= 104/3
= 34 2/3 sL
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Verified answer
ApLik4si InTeg12aL
Luas
= 2 ∫√(x + 1) dx [8...0]
= 2 ∫(x + 1)^1/2 d(x + 1)
= 4/3 (x + 1)^3/2
= 4/3 ( (8 + 1)^3/2 - (0 + 1)^3/2 )
= 4/3 (27 - 1)
= 104/3
= 34 2/3 sL