L Δ besar :
[tex] = \frac{1}{2} at \\ = \frac{1}{2} \times 14 \times (12 + 8 + 3) \\ = 7 \times 23 \\ = 161 \: cm^{2} [/tex]
L Δ kecil :
[tex] = \frac{1}{2} at \\ = \frac{1}{2} \times 9 \times 8 \\ = 9 \times 4 \\ = 36 \: {cm}^{2} [/tex]
Jadi, luas daerah yang diarsir
L Δ besar - L Δ kecil = 161 - 36
= 125 cm²
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L Δ besar :
[tex] = \frac{1}{2} at \\ = \frac{1}{2} \times 14 \times (12 + 8 + 3) \\ = 7 \times 23 \\ = 161 \: cm^{2} [/tex]
L Δ kecil :
[tex] = \frac{1}{2} at \\ = \frac{1}{2} \times 9 \times 8 \\ = 9 \times 4 \\ = 36 \: {cm}^{2} [/tex]
Jadi, luas daerah yang diarsir
L Δ besar - L Δ kecil = 161 - 36
= 125 cm²