Penyelesaian
Luas lingkaran:
diameter:
√6²+8²
=√36+64
=√100
=10cn
.
r=5cm
L=πr²
L=3,14×5×5
L=78,5cm²
Luas layang-layang
L=½×d1×d2
L=½×(8+14)×(6×2)
L=½×(22)×12
L=22×6
L=132cm²
132+78,5=210,5cm²(c.)
Semoga bermanfaat
√6² + 8²
= √(6(6) + (8(8)
= √36 + 64
= √100
= √10²
= 10/2 = 5 CM (R)
L.LINGKARAN = πR²
= 3,14(5(5)
= 3,14(25)
= 78,5 CM²
L.LAYANG-LAYANG :
= 1/2D1D2
= 1/2(8 + 14(6(2)
= 1/2(22(12)
= 1/2(264)
= 1(264/2)
= 132 CM²
L.GAB :
L1 + L2
= (78,5 + 132)CM²
= 210,5 CM²
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Penyelesaian
Luas lingkaran:
diameter:
√6²+8²
=√36+64
=√100
=10cn
.
r=5cm
L=πr²
L=3,14×5×5
L=78,5cm²
.
Luas layang-layang
L=½×d1×d2
L=½×(8+14)×(6×2)
L=½×(22)×12
L=22×6
L=132cm²
.
132+78,5=210,5cm²(c.)
Semoga bermanfaat
√6² + 8²
= √(6(6) + (8(8)
= √36 + 64
= √100
= √10²
= 10/2 = 5 CM (R)
L.LINGKARAN = πR²
= 3,14(5(5)
= 3,14(25)
= 78,5 CM²
L.LAYANG-LAYANG :
= 1/2D1D2
= 1/2(8 + 14(6(2)
= 1/2(22(12)
= 1/2(264)
= 1(264/2)
= 132 CM²
L.GAB :
L1 + L2
= (78,5 + 132)CM²
= 210,5 CM²