luas bangun diatas ada....cm²
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L = L segitiga + L trapesium + L ½ lingkaran
SEGITIGA
a = 2 × 14
= 28 cm
t = 42 cm
L = ½ × a × t
L = ½ × 28 × 42
L = 588 cm²
TRAPESIUM
a = 4 × 14
= 56 cm
b = 4 × 21
= 84 cm
t = 21 cm
L = ½ × t × (a + b)
L = ½ × 21 × (56 + 84)
L = ½ × 21 × 140
L = 1.470 cm²
½ LINGKARAN
r = 21 cm
L = ½ × π × r²
L = ½ × 22/7 × 21²
L = 693 cm²
L = 588 cm² + 1.470 cm² + 693 cm²
L = 2.751 cm²
Jawabannya a. 2.751 cm²