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100 = s²
√100 = √s²
10 = s
a = t limas
= 12 cm
b = s : 2
= 10 cm : 2
= 5 cm
a² + b² = c²
12² + 5² = c²
144 + 25 = c²
169 = c²
√169 = √c²
13 = c
t sisi tegak = c
= 13 cm
LP = La + Jumlah L sisi tegak
= s² + 4(1/2 × a × t)
= 10² + 4(1/2 × 10 × 13)
= 100 + 4(65)
= 100 + 260
= 360 cm²
Jadi luas permukaannya adalah 360 cm²
Cari tinggi segitiga :
Sehingga, luas seluruh bidang sisi limas :