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L.lingkaran = π.r.r
154 =22/7.r.r
r^2 = 154.7/22
r^2 = 49
r = √49
r = 7cm
s^2 = t^2 + r^2
= 24^2 + 7^2
= 576 + 49
= 625
s =√625
= 25
L.prmkaan kerucut=π.r.s + π.r^2
=22/7.7.25+22/7.7^2
=550+154
= 704
jadi, luas permukaan kerucut adalah 704cm//