A= 2^a . 3^b
Raiz de A= 2^(a/2) . 3^(b/2)
[(a/2)+1] . [(b/2)+1]=12
Descomponemos 117 = 3^2 . 13
(2a+1)(2b+1)=3^2 . 13
a=4
b=6
De modo que, los valores de a y b son 4 y 6; respectivamente
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
A= 2^a . 3^b
Raiz de A= 2^(a/2) . 3^(b/2)
[(a/2)+1] . [(b/2)+1]=12
Descomponemos 117 = 3^2 . 13
(2a+1)(2b+1)=3^2 . 13
a=4
b=6
De modo que, los valores de a y b son 4 y 6; respectivamente