Question

½log(x²-3)-½logx=-1, berapakah nilai x ?

Answer 1

Verified answer

LogAritMa

(1/2)'log (x² - 3) - (1/2)'log x = -1

(1/2)'log ((x² - 3)/x) = -1

(x² - 3)/x = (1/2)^-1

(x² - 3)/x = 2

kali silang

x² - 3 = 2x

x² - 2x - 3 = 0

(x - 3)(x + 1) = 0

x = 3 ; x = -1

Syarat numerus : > 0
x > 0
x² - 3 > 0 ---> x² > 3 

NiLai x yg memenuhi :
x = 3


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