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Lo = 1 m
L = 1,04 m
ΔT = 50 K
dit : α ?
dijawab :
ΔL = 1,04 - 1 = 0,04 m
α = ΔL/LoxΔT
= 0,04 / 1 x 50
= 0,04 / 50
= 0,0008/°K