" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
setarakan reaksi diatas..
nanti akan didapat perbandingan mol besi 2 oksida dengan CO2 = 2:3
maka mol CO2 sama dengan 0,2 x 3/2 = 0,3
Volume CO2= 0,3 x 22,4= 6,72 L
n CO2 = 3/2 mol Fe2O3 (STP)
= 3/2 0.2 = 0.3
2Fe2O3 + 3C => 4Fe + 3CO2 (setara)
m 0.2 - - -
b 0.2 - 4/2 0.2 3/2 0.2
s 0 0.4 0.3
Volume gas CO2
n = v/22.4
v = n 22.4
= 0.3 mol x 22.4 liter
= 6.72 liter