Question

Log²a adlh notasi (log a)². Berapa nilai a yg memenuhi 2×log ²a+log a= 6?

Answer 1

2.log²a + loga = 6
2,log²a + loga - 6 = 0

misal loga = x

2x² + x - 6 = 0
(2x - 3)(x + 2) = 0
x = 3/2
x = -2

x = 3/2
loga = 3/2
a = 10^(3/2)
a = √10³
a = √1000
a = 10√10

atau

x = -2
loga = -2
a = 10^(-2)
a = 1/10²
a = 1/100