Question

Log2=a log3=b
3log18=? 6log72=?

Answer 1

3'log 18 = log 18/log 3 
= log 2 +log 3^2 / (log3)
= (log 2 + 2. log 3) / (log 3)
= (a + 2b) / (b)
.
6'log 72 = log 72/log 6
= log 8+ log 9 / (log 2 +log 3)
= (3 . log 2 + 2 log 3 )/ (log 2 +log 3)
= (3 a + 2b)/(a + b)

Answer 2

3log18= log18/log3
=log3×3×2/log3 = log3+log3+log2/log3 = 2b+a/b

6log72 = log72/log6
=log2×2×2×3×3/log2×3
=log2^3+log3^2/log2+log3
=3×log2+2×log3/log2+log3
=3a+2b/a+b

semoga bermanfaat:)