Question

Log2=0,3010 dan log3=0,4771, maka log 12 = ?

Answer 1

Answer 2

Log 2= 0.3010  log  3 = 0,4771
log 12 = log 3 x 4
          = log 3 + log 2 pangkat 2
          = log 3 + 2 log 2
         = 0,4771 + 2(0,3010)
         = 0,4771 + 0,6020
         = 1,0791