( )log base 2 de 5 + log base 2 (2x+3)=5.... Question from @jesusito01222

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jesusito01222 @jesusito01222

November 2018 2 22 Report

( )log base 2 de 5 + log base 2 (2x+3)=5

¡Notificar abuso! Log base 2(5(2x+3))=5
2^(log base 2(5(5x+3)))=2^5
5(2x+3)=32
10x+15=32
10x=32-15
10x=17
x=17/10

2 votes Thanks 1

Jeizon1L Propiedades:

$\item{1)} \ log_b A + log_b B = log_b (A*B)


\item{2)} Si log_b N = x \to b^x=N$

En base a estas propiedades, resolvemos:

$log_2 5+log_2 (2x+3) = 5

\ \

log_2(5*(2x+3)) = 5

\ \

5*(2x+3) = 2^5

\ \

10x+15 = 32

\ \

10x = 17

\ \

\boxed{\boxed{x = \frac{17}{10}=1.7}}$

Eso es todo! Saludos! Jeizon1L

1 votes Thanks 0