Question

²log 3= m, maka pangkat 27 log 12=...

Answer 1

27'log 12 = 2'log 12 / 2'log 27
= [2'log 2^2 + 2'log 3] / [ 2'log 3^3 ]
= [ 2' 2'log 2 + 2'log 3 ]/ [3. 2'log 3]
= ( 2 + m) / (3m)

Answer 2

Pangkat 2 lg 3 = m
lg 3 / lg 2 = m
lg 3 = m . lg 2

pangkat 27 lg 12
= lg 12 / lg 27
= lg 2 . 6 / lg 3 . 9
= lg 2 + lg 6 / lg 3 + lg 9
= lg 2 + lg 6 / m . lg 2 + lg 9
= lg 6 / m + lg 9
*lg 2 dg lg 2 dicoret