Jawaban:
1
Penjelasan dengan langkah-langkah:
²log3=(²log e) × ln(3) = ln(3)/ln(2)
jadi a=3 dan b=2
maka a-b =3-2=1
[tex] {}^{a} logb \: \to \: \frac{ ln(b) }{ ln(a) } [/tex]
Maka
[tex] { }^{2} log3 = \frac{ ln(3) }{ ln(2) } [/tex]
a - b
= 3 - 2
= 1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
1
Penjelasan dengan langkah-langkah:
²log3=(²log e) × ln(3) = ln(3)/ln(2)
jadi a=3 dan b=2
maka a-b =3-2=1
Verified answer
Penjelasan dengan langkah-langkah:
[tex] {}^{a} logb \: \to \: \frac{ ln(b) }{ ln(a) } [/tex]
Maka
[tex] { }^{2} log3 = \frac{ ln(3) }{ ln(2) } [/tex]
a - b
= 3 - 2
= 1