Lim (x→1) = (x/x-1 - 1/in x) Lim (x→1) = (x in x - x + 1 / (x-1) in x) Lim (x→1) = (x in x - x + 1 / x in x- in x) Lim (x→1) = (in x + 1 - 1 / in x +1 - 1/x) Lim (x→1) = (x. in x / x. in x + x -1) Lim (x→1) = (in x + 1 / in x + 1 + 1) = (in x + 1 / in x + 2)
Verified answer
JawabLimit (x→ 1) { x/(x -1) - 1/ln x) = 1/2
Verified answer
Jawab:Lim (x→1) = (x/x-1 - 1/in x)
Lim (x→1) = (x in x - x + 1 / (x-1) in x)
Lim (x→1) = (x in x - x + 1 / x in x- in x)
Lim (x→1) = (in x + 1 - 1 / in x +1 - 1/x)
Lim (x→1) = (x. in x / x. in x + x -1)
Lim (x→1) = (in x + 1 / in x + 1 + 1)
= (in x + 1 / in x + 2)
x → 1 = Lim = 1/2
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