Lingkaran dalam segitiga sama sisi mempunyai jari-jari 2 akar pgkat 3. Hitunglah keliling segitiga trsbut
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KΔ
2√3 cm = 2 x L Δ
KΔ
12 = 2 x LΔ
KΔ
= 2 x 1/2 x s x s
= 1 s
12 = s
K Δ = 12 X 3
= 36 cm
2) hipotenuse : √12 + √16
= √144 + 256
= √400
= 20 cm
2 x LΔ
KΔ
= 12 x 16
KΔ
= 192
12 + 16 + 20
= 192
48
= 4
L lingkaran = 3,14 x (2 x 4)