Lingkaran berpusat di (0,0) dan melalui titik (7,24) berjari jari???.... Question from @denysms

September 2018 2 1K Report

Lingkaran berpusat di (0,0) dan melalui titik (7,24) berjari jari???

akbararya R= $\sqrt{24 ^{2}+7^2 }$
=25 satuan panjang

2 votes Thanks 7

IcukSugiarto $\bold{\underline{Solution:}}\\diketahui\ pusat\ O(0,0)\\titik\ (7,24)\\\\persamaan\ lingkaran\ dengan\ pusat\ O(0, 0)\\dan\ berjari-jari\ r\ adalah:\\\boxed{r^{2}=x^{2}+y^{2}}~~~~atau~~~~~\boxed{r= \sqrt{x^{2}+y^{2}} }\\\\sehingga:\\r= \sqrt{x^{2}+y^{2}}\\r= \sqrt{7^{2}+24^{2}}\\r= \sqrt{49+576}\\r= \sqrt{625} \\r= 25\\\\\bold{jadi\ jari-jarinya\ ialah:\ 25\ satuan\ panjang}$

1 votes Thanks 4

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