Lim z → 82z + √81 - 3! ÷ 2 + z¹ = ...... Question from @mzxnaa25

$\huge\tt\color{ff6666}{}\color{ffb266}{P}\color{b2ff66}{e}\color{66b2ff}{n}\color{6666ff}{y}\color{b266ff}{e}\color{ff66ff}{l}\color{ff66ff}{e}\color{ff66b2}{saian}$

Lim z → 8

2z + √81 - 3! ÷ 2 + z¹

=> 2(8) + √81 - 3! ÷ 2 + 8¹

=> (2 × 8) + 9 - (3 × 2 × 1) ÷ 2 + 8

=> 16 + 9 - 6 ÷ 2 + 8

=> 16 + 9 - (6 ÷ 2) + 8

=> 16 + 9 - 3 + 8

=> 25 - 3 + 8

=> 22 + 8

=> 30

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Zan643

$\sf lim_{z\to8} \: \: (2z + \sqrt{81} - 3! \div 2 + {z}^{1} )$

$\sf lim_{z\to8} \: \: (2(8) + \sqrt{ {9}^{ \frac{2}{2} } } - ((3 \times 2 \times 1) \div 2 )+ {8}^{1}$

$\sf lim_{z\to8} \: \: (16 + 9 - (6 \div 2) + 8)$

$\sf\lim_{z\to8} \: \: (25 - 3 + 8)$

$\sf lim_{z\to8} \: \: (22 + 8)$

$\sf lim_{z\to8} \: \: \blue{30}$

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Zzz!!

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