The limit of the function f(x) = x^3 + 2x^2 - 8x + 1 as x approaches 2 can be found using substitution:
f(2) = 2^3 + 2 * 2^2 - 8 * 2 + 1 = 8 + 8 - 16 + 1 = 1
So, the limit of the function as x approaches 2 is 1.
Therefore,
lim x → 2 (x^3 + 2x^2 - 8x + 1) = 1
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The limit of the function f(x) = x^3 + 2x^2 - 8x + 1 as x approaches 2 can be found using substitution:
f(2) = 2^3 + 2 * 2^2 - 8 * 2 + 1 = 8 + 8 - 16 + 1 = 1
So, the limit of the function as x approaches 2 is 1.
Therefore,
lim x → 2 (x^3 + 2x^2 - 8x + 1) = 1