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lim x ⇒0 (√x (√x+x)-x) / √x+x
lim x⇒0 (x+x√x-x) / √x + x
lim x⇒0 x√x/√x + x
dirasionalkan sehingga
lim x⇒0 {x√x * (√x - x) } / (√x + x )(√x - x)
lim x⇒0 (x²-x²√x) / (x-x²)
lim x⇒0 x²(1-√x) / x(1-x)
lim x⇒0 x (1-√x) / (1-√x)(1+√x)
lim x⇒0 x/1+√x
lim x⇒0 0/1+√0
lim x⇒0 0
= 0