Lim (3-x) (3x+2) per (4x+1) (2x-1)... ad yg bsa mnjawab,, aku bngung
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![\lim_{n \to \infty} [\frac{(3-x)(3x+2)}{(4x+1)(2x-1)}]=\lim_{n \to \infty} [\frac{-3x^2+7x+6}{(8x^2-2x-1}]](https://tex.z-dn.net/?f=+%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%5B%5Cfrac%7B%283-x%29%283x%2B2%29%7D%7B%284x%2B1%29%282x-1%29%7D%5D%3D%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%5B%5Cfrac%7B-3x%5E2%2B7x%2B6%7D%7B%288x%5E2-2x-1%7D%5D "\lim_{n \to \infty} [\frac{(3-x)(3x+2)}{(4x+1)(2x-1)}]=\lim_{n \to \infty} [\frac{-3x^2+7x+6}{(8x^2-2x-1}]")
![=\lim_{n \to \infty} [\frac{-3x^2+7x+6}{(8x^2-2x-1}]* \frac{ \frac{1}{x^2} }{ \frac{1}{x^2} }](https://tex.z-dn.net/?f=%3D%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%5B%5Cfrac%7B-3x%5E2%2B7x%2B6%7D%7B%288x%5E2-2x-1%7D%5D%2A+%5Cfrac%7B+%5Cfrac%7B1%7D%7Bx%5E2%7D+%7D%7B+%5Cfrac%7B1%7D%7Bx%5E2%7D+%7D "=\lim_{n \to \infty} [\frac{-3x^2+7x+6}{(8x^2-2x-1}]* \frac{ \frac{1}{x^2} }{ \frac{1}{x^2} }")
![=\lim_{n \to \infty} [\frac{ \frac{-3x^2+7x+6}{x^2} }{ \frac{8x^2-2x-1}{x^2} }]](https://tex.z-dn.net/?f=%3D%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%5B%5Cfrac%7B+%5Cfrac%7B-3x%5E2%2B7x%2B6%7D%7Bx%5E2%7D+%7D%7B+%5Cfrac%7B8x%5E2-2x-1%7D%7Bx%5E2%7D+%7D%5D "=\lim_{n \to \infty} [\frac{ \frac{-3x^2+7x+6}{x^2} }{ \frac{8x^2-2x-1}{x^2} }]")
![=\lim_{n \to \infty} [\frac{-3+ \frac{7}{x}+ \frac{6}{x^2}}{ 8- \frac{2}{x}- \frac{1}{x^2}}]](https://tex.z-dn.net/?f=%3D%5Clim_%7Bn+%5Cto+%5Cinfty%7D+%5B%5Cfrac%7B-3%2B+%5Cfrac%7B7%7D%7Bx%7D%2B+%5Cfrac%7B6%7D%7Bx%5E2%7D%7D%7B+8-+%5Cfrac%7B2%7D%7Bx%7D-+%5Cfrac%7B1%7D%7Bx%5E2%7D%7D%5D "=\lim_{n \to \infty} [\frac{-3+ \frac{7}{x}+ \frac{6}{x^2}}{ 8- \frac{2}{x}- \frac{1}{x^2}}]")
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