Ba(OH)2 + 2 HCl = BaCl2 + 2 H2O
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Ba(OH)2 + 2 HCl = BaCl2 + 2 H2O
Ba(OH)2 = 137 g/molHCl = 36 g / mol
BaCl2 = 208 g/mol
H2O = 18 g /mol
Ba (OH)2 + 2HCl → Ba Cl2 +2H2O
137g +2( 36) g → 208 g + 2( 18 g)
137 g + 72 g → 208 g + 36 g
169 g →