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Tenemos.
2. 4 . 6 . 8 . 10...............n
Se trata de una progresion aritmetica.
an = Ultimo termino
a₁ = 1er termino = 2
n = Numero de terminos = n
d = diferencia = 4 - 2 = 2
Formula.
an = a₁ + (n - 1) * d
an = 2 + (80 - 1) * 2
an = 2 + 79*2
an = 2 + 158
an = 160
Formula para hallar la suma de los 80 terminos.
S = (an + a₁)n/2
S = (160 + 2) * 80/2 Simplificas el 2
S = 162 * 40
S = 6480
- 1 . - 3 . - 5 . - 7........................... - n
d = - 3 - ( - 1) = - 3 + 1 = - 2
a₁ = - 1
n = 80
an = ?
an = a₁ + (n - 1) * d
an = - 1 + (80 - 1) * - 2
an = - 1 + 79 * - 2
an = - 1 - 158
an = - 159
S₁ = (a₁ + an) * n/2
S₁ = ( - 1 - 159) * 80/2
S₁ = ( - 160) * 40
S₁ = - 6400
S - S₁ =
6480 - ( - 6400) =
6480 + 6400 =
12880
Respuesta.
12880