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Cantidad en Moles del soluto:
1 mol CaCl2 ------------ 111.0 g
moles CaCl2 ----------- 10 g
moles CaCl2 = 10 * 1 / 111.0
moles CaCl2 = 10 / 111.0
moles CaCl2 = 0.090
entonces:
Volumen = moles / molaridad
V = 0.090 / 0.5
V = 0.180 L