Layang layang ABCD,panjang diadgonal AC = 6cm dan BD = (×+1)cm.Jika luas layang layang itu 48cm2,maka hitunglah: a.nilai x? b.panjang diagonal BD?
AgnesAL3
A.) L.Layang-layang = d1 × d2 / 2 48 = 6 × (x+1) / 2 48 = 6x + 6 / 2 48 = 6x x = 48/6 x = 8 BD = x + 1 BD = 8 + 1 = 9
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