Question

Larutan NH4CL 0,1 M terhidrolisis 1%,hitunglah PH larutan tersebut!

Answer 1

Α = √kb / M
1/100 = √kb / 0,1
(0,01)² = Kb / 0,1
Kb = (0,01)² × 0,1
     = 1 × 10^-5
[H+] = √Kw / Kb × G
     = √10^-14 / 10^-5 × 10^-1
     =10^-5
Ph = -log 10^-5
Ph = 5

Answer 2

Kalo nggak salah ph nya 5