Question

Larutan NH4Cl 0.1 M terhidrolisis 1% pH larutan tersebut adalah

Answer 1

Α = √Ka/NH4Cl
1%=√Ka/01
(0,01)²=(√Ka/0,1)²
0,0001 = Ka/0,1
Ka = 10⁻⁵
H⁺ = √KaxNH4Cl
H⁺ = √10⁻⁵ x 0,1
H⁺ = √10⁻⁶
H⁺ = 10⁻³
pH = -log H⁺
pH = -log 10⁻³
pH = 3